fix: Fixing the issue of the object.subset method failing to correctly compare array relationships (#5969)

Fixes：#5968

Signed-off-by: DCRUNNN <458891338@qq.com>

test/cases/testdata/subset/test-subset.yaml

@@ -384,5 +384,55 @@ cases:
 
     note: subset/array and set 2
     query: data.test.test_result = x
+    want_result:
+      - x: true
+  
+  - data:
+    modules:
+      - |
+        package test
+
+        A := [1,2,3,4,5,6]
+        B := [4,5,6,8]
+
+        AsubB := object.subset(A, B)
+        BsubA := object.subset(B, A)
+
+        # Notice that there isn't really a well-defined way to "match" the two
+        # nested sets to one another, so we B is not a subset of A in this
+        # case.
+
+        test_result {
+          not AsubB     # B is not a subset of A
+          not BsubA     # A is not a subset of B
+        }
+
+    note: subset/arrays 5
+    query: data.test.test_result = x
+    want_result:
+      - x: true
+
+  - data:
+    modules:
+      - |
+        package test
+
+        A := [1,2,3,4,5,6]
+        B := [8,9,10]
+
+        AsubB := object.subset(A, B)
+        BsubA := object.subset(B, A)
+
+        # Notice that there isn't really a well-defined way to "match" the two
+        # nested sets to one another, so we B is not a subset of A in this
+        # case.
+
+        test_result {
+          not AsubB     # B is not a subset of A
+          not BsubA     # A is not a subset of B
+        }
+
+    note: subset/arrays 6
+    query: data.test.test_result = x
     want_result:
       - x: true

topdown/subset.go

@@ -193,12 +193,12 @@ func arraySubset(super, sub *ast.Array) bool {
 			return true
 		}
 
-		if superCursor == super.Len() {
+		if superCursor+subCursor == super.Len() {
 			return false
 		}
 
 		subElem := sub.Elem(subCursor)
-		superElem := sub.Elem(superCursor + subCursor)
+		superElem := super.Elem(superCursor + subCursor)
 		if superElem == nil {
 			return false
 		}